Making 500 mL of a 0.1 M solution from a 2 M stock
V1 = (0.1 × 500) / 2 = 25 mL of stock, topped up with solvent to 500 mL total.
Result
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Diluting a solution adds solvent but not solute — the amount of dissolved substance stays the same before and after. Since amount equals concentration times volume, C1×V1 (before) must equal C2×V2 (after), which is the whole basis of the calculation.
The most common question is "how much stock do I measure out?" — that solves for V1 given the stock concentration, the target concentration and the final volume you want to make.
C1 × V1 = C2 × V2
V1 = (0.1 × 500) / 2 = 25 mL of stock, topped up with solvent to 500 mL total.
If the stock is 5 M, the resulting concentration is C2 = (5 × 10) / 200 = 0.25 M.
Not V2 itself — you add V2 − V1, because the stock volume V1 you measure out already contributes to the final volume. Measure V1 of stock into your container, then add solvent up to the V2 mark, rather than adding a full V2 of solvent on top of V1.
Yes, one step at a time: solve for V1 in the first dilution, then use its result (the new C2) as the C1 of the next dilution step, and so on.
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